100=15x^2

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Solution for 100=15x^2 equation:



100=15x^2
We move all terms to the left:
100-(15x^2)=0
a = -15; b = 0; c = +100;
Δ = b2-4ac
Δ = 02-4·(-15)·100
Δ = 6000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6000}=\sqrt{400*15}=\sqrt{400}*\sqrt{15}=20\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{15}}{2*-15}=\frac{0-20\sqrt{15}}{-30} =-\frac{20\sqrt{15}}{-30} =-\frac{2\sqrt{15}}{-3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{15}}{2*-15}=\frac{0+20\sqrt{15}}{-30} =\frac{20\sqrt{15}}{-30} =\frac{2\sqrt{15}}{-3} $

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